Code & Fun

第68天。

今天的题目是Longest Continuous Increasing Subsequence:

Given an unsorted array of integers, find the length of longest continuous increasing subsequence (subarra y).

Example 1:
Input: [1,3,5,4,7]
Output: 3
Explanation: The longest continuous increasing subsequence is [1,3,5], its length is 3.
Even though [1,3,5,7] is also an increasing subsequence, it’s not a continuous one where 5 and 7 are separated by 4.
Example 2:
Input: [2,2,2,2,2]
Output: 1
Explanation: The longest continuous increasing subsequence is [2], its length is 1.
Note: Length of the array will not exceed 10,000.

题目比较简单,只需要遍历一遍所有元素,然后每次都比较它和它前面一个元素的大小即可:

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int findLengthOfLCIS(vector<int>& nums) {
if (nums.size() == 0) return 0;
int ret = 0;
int a = 1;
for(int i = 0;i + 1 < nums.size();i++)
if (nums[i] < nums[i+1]) a++;
else {
ret = max(a,ret);
a = 1;
}
return max(a,ret);
}

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